32x^2+45x-32=0

Solution for 32x^2+45x-32=0 equation:

32x^2+45x-32=0

a = 32; b = 45; c = -32;
Δ = b2-4ac
Δ = 452-4·32·(-32)
Δ = 6121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-\sqrt{6121}}{2*32}=\frac{-45-\sqrt{6121}}{64}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+\sqrt{6121}}{2*32}=\frac{-45+\sqrt{6121}}{64}
$